Physics, asked by aseel5265, 6 months ago

Temperature of patch of skin of a healthy person is 37°c.Due to viral fever temperature increases by 5.4%.Then percentage change in rate of heat radiation from patch of skin is nearly?

Answers

Answered by pranay9018
3

Answer:

Hope this Hint helps you!

Explanation:

use this hint and solve yourselves you get 2.6%

change in radiation of Heat

Attachments:
Answered by monishashkl
1

Answer:

The percentage change in the rate of the heat radiation from the patch of the skin of the person is 5.4%

Explanation:

Here we have been mentioned that the particular temperature of the patch of skin of a healthy person is found to be 37°C. Due to the viral fever to the person, his person increases by 5.4%

The percentage change in the rate of the radiation of heat from the patch of the skin can be found as below:

Here the temperature increases by 5.4 % therefore the new temperature is:

37°C + 5.4% of 37°C

= 37°C + \frac{5.4}{100} × 37°C

= 37° C + 1.998°C

= 38.998°C

Which is approximately equal to 39°C

Now the percentage change in temperature = \frac{39-37}{37} ×100%

= \frac{2}{37} × 100%

= 5.4%

Therefore the percentage change in the rate of heat radiation from the patch of the skin is 5.4%

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