Tempestt graphs a function that has a maximum located at (–4, 2). Which could be her graph? On a coordinate plane, a parabola opens up. It goes through (negative 6, 6), has a vertex at (negative 4, 2), and goes through (negative 2, 6). On a coordinate plane, a parabola opens up. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6). On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 2), has a vertex at (negative 4, 2), and goes through (negative 2, negative 2). On a coordinate plane, a parabola opens down. It goes through (2, negative 2), has a vertex at (4, 2), and goes through (6, negative 2).
Answers
Given : Tempestt graphs a function that has a maximum located at (–4, 2)
To find : Which could be her graph
Solution:
Tempestt graphs a function that has a maximum located at (–4, 2)
=> for x = - 4 , the y = 2 is the maximum value
hence ( - 4 , 2) is the vertex
hence every point on graph would be less than 2 on y - axis for any x
It goes through (- 6, 6), has a vertex at (- 4, 2), and goes through -2, 6).
not possible as y = 6 > 2
. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6).
not possible as y = 6 > 2
it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).
vertex (-4 , 2)
y < 2
This Could be her Graph
It goes through (2, -2), has a vertex at (4, 2), and goes through (6, -2).
not possible as vertex here is (4 , 2) instead of (-4,2)
Her Graph
On a coordinate plane, a parabola opens down it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).
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Answer:
C
Step-by-step explanation: