Question

Ten friends share 21 chocolate bars equally among themselves.How many chocolates will two of the friends have altogether?​

Answer 1

Two friends will have a total of 4$\frac{1}{5}$ chocolates together.

Given:

Number of friends = 10

Number of chocolates = 21

To find: Number of chocolates with 2 friends together

Solution:

We are given,

Number of chocolates = 21

Number of friends = 10

By the unitary method,

Number of chocolates with one friend = 21/10

⇒ Number of chocolates with 2 friends = 2 x 21/10

= 42/10 = 4.2 = 4$\frac{1}{5}$

∴ Two friends will have a total of 4$\frac{1}{5}$ chocolates together.

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Answer 2

Answer:

Two friends will share a total of 4 1/5 chocolates.

Step-by-step explanation:

Given:

Ten friends divide 21 chocolate bars evenly among themselves.

The number of friends is ten.

The number of chocolates is 21.

To determine: How many chocolates will two friends have in total.

Number of chocolates with two friends together.

Solution:

We have been given,

The number of chocolates is 21.

The number of friends is ten.

According to the unitary method,

Number of chocolates shared with one friend = 21/10

Number of chocolates shared by two friends = 2 x 21/10

= 42/10 = 4.2 = 4 1/5

As a result of the given condition, two friends will share a total of four chocolates.

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