Math, asked by uditarora, 1 year ago

Ten houses line on one side of a street. The average space between houses is 60 feet more than the
average width of each house. A side walk starts 60 feet before the first house and ends 60 feet
after the last house. If the total length of sidewalk is 3206 feet, find the average width of each
house.
(A) 120 ft (B) 130 ft (C) 134 ft (D) 147 ft
(E) 206 ft

Answers

Answered by drbinodpokhrel
1

Answer:

Step-by-step explanation:

Let the avg. width of each houses be x.

Avg. Space between two houses is x + 60

By question,

60 + 10x + 9(x + 60) + 60 = 3206

Or 10x + 9x + 540 + 120 = 3206

Or 19x + 660 = 3206

Or 19x = 3206 - 660

Or 19x = 2546

Or x = 2546/19

Or x = 134

Hence average width of each house is 134 feet.

Answer : C

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