Math, asked by mishti912, 9 months ago



Ten men, working for 6 days of 10 hours
finish = of a piece of work. How many men
working at the same rate and for thes
number of hours each day, will be required
complete the remaining work in 8 days?​

Answers

Answered by MrYash77
1

Answer:

bro।

one day working of 10 man is 5 by 21 into 1 by 6 one day working of one man is equal to 5 by 21 into 1 by 6 into 1 by 10 a day working of one man is equal to 5 by 21 into 1 by 6 into 1 by 10 in 28 which is equal to 2 by 63 remaining work 1 minus 5 by 21 which equals to 16 by 21 hence number of men required to complete

Answered by nvedant682
1

Answer:

Step-by-step explanation:

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