Question

Ten percent of the red balls were added to twenty percent of the blue balls and the total was 24. Yet three times the number of red balls exceeds the number of blue balls by 20. How many were red balls and how many were blue balls?

Answer 1

Answer:

red balls are 4

and blue balls are 20

Answer 2

40 red balls and 100 blue balls

Explanation:

Given: Ten percent of the red balls were added to twenty percent of the blue balls and the total was 24. Yet three times the number of red balls exceeds the number of blue balls by 20.

Let red balls be r and blue balls be b.

Then we get 10r/100 + 20b/100 = 24

r + 2b = 240 ---------------------(1)

3r - b = 20 ---------------------(2)

(1)---------------------    r + 2b = 240

(2) * 2 --------------    6r  - 2b = 40

Adding, we get ----- 7 r = 280

So r = 280 / 7 = 40  

Substituting r = 40 in equation 1, we get 40 + 2b = 240

2b = 240 - 40 = 200

b = 200 / 2 = 100

So there were 40 red balls and 100 blue balls.