Question

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be. Find their present age.

Answer 1

Answer:

Given :-

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be

To Find :-

Present ages

Solution :-

Let us assume that

Ten years ago

Age of son = a

Age of father = 12a

Present age will be

Age of son = a + 10

Age of father = 12a + 10

12a + 10 + 10 = 2(a + 10 + 10)

12a + 20 = 2(a + 20)

12a + 20 = 2a + 40

12a - 2a = 40 - 20

10a = 20

a = 20/10

a = 2

Therefore,

Present age of son = a + 10

Present age of son = 2 + 10

Present age of son = 12 years

Present age of father = 12a + 10

Present age of father = 12(2) + 10

Present age of father = 24 + 10

Present age of father = 34 years

Answer 2

Answer:

• Present age of father = 34 years
• Present age of son = 12 years.

Step-by-step explanation:

Let the present age of father be "f" and son's age be "s".

Question :-

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be. Find their present age.

Given :-

• Ten year ago ,father was 12 times as old as his son
• 10 years hence, he will be twice as old as his son will be.

SOLUTION AND STEPS ARE IN ATTACHMENT.