Question

ten year ago mother was 4 times old as his son and after 3 years ratio of their ages will be 15:7 find their age​

Answer 1

Answer:

Mothers age is 18

Son age is 2

Answer 2

Answer:

the age of the son is 18 and of his mother is 42.

Step-by-step explanation:

let the present age of the son be x

and age of the mother be y

10years ago age of the boy was (x-10)

and age of the mother 10years ago was y-10

and

4(x-10)=(y-10)

this gives

4x-y=30

y=4x-30.....................(1)

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After 3 years the age of the son and mother will be

(x+3) and (y+3) respectively

according to the question

y+3/x+3 = 15/7

(y+3)(7)=(x+3)(15)

7y+21=15x+45

x=(7y+21-45)/15

x=(7y-24)/15............…........(2)

solving both equations:putting value of y from equation (1) in equation (2)

we get x=18

and putting value of x in equation (1)

we get y=42

Thanks:)

Hope it helps you!