Ten years ago a father was 12 times as old as his son. 10 years,hence father will be twice as old as his son. Find their present ages ?
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Answer:
34 and 12
Step-by-step explanation:
using the ratio method
ten years ago 12:1
ten years hence 2:1
equaling the ratios
12:1 and 22:11
so 10 units = 20
1 unit = 2
so the ages ten years before are 24 and 2
so the present age of father and son are 34 and 12 respectively
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