Math, asked by gorekamal, 11 months ago

Ten years ago a father was 12 times as old as his son. 10 years,hence father will be twice as old as his son. Find their present ages ?

Answers

Answered by rithinv78
1

Answer:

34 and 12

Step-by-step explanation:

using the ratio method

ten years ago 12:1

ten years hence 2:1

equaling the ratios

12:1  and 22:11

so 10 units = 20

1 unit = 2

so the ages ten years before are 24 and 2

so the present age of father and son are 34 and 12 respectively

Answered by 9340
3

This is the required answer

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