Question

Ten years ago a father was seven times as old as his son two years hence twice his age will be equalto five times his sons. What is the present age of son?​

Answer 1

Answer:

Let son's age 10 years ago be x years.

Then, man's age 10 years ago = 7x years

Son's present age = (x + 10) years,

Man's present age = (7x + 10) years

∴2[(7x+10)+2] = 5[(x+10)+2] ⇒2(7x+12)=5(x+12) ⇒14x+24=5x+60 ⇒9x=36 ⇒x=4

Son's present age = (x + 10) years

= (4 + 10) years

= 14 years

Step-by-step explanation:

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Answer 2

Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age ... Son's present age = (x + 10) years ,