Question

ten years ago a father was six times as old his daughter after 10 years he will be twice as old as his daughter determine their present age

Answer 1

Hey dear friend

Let the age of father be x and daughter be y
According to question

10 years ago
(x-10)=6(y-10).
x-10=6y-60
x=6y-50

After 10 years
(x+10)=2(y+10). eq.

Substituting x=6y-50 in eq.
we get
=>6y-50+10=2(y+10)
=>6y-40=2y+20
=>4y=60
=>y=15

So, x=6*15-50
x=40

So the present age of father is 40 years
and present age of daughter is 15 years

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