Ten years ago, A's age was half of B's age. If
on the ratio of their present ages is 3 : 4, what
will be the sum of their present ages ?
Answers
Answered by
12
Answer:
35
Step-by-step explanation:
ten year's ago A's age : 1/2 of the B's age
at present A/B : 3/4
then A+10 / B+ 10 = 3/4
A+10 / 2A + 10 = 3/4
4A+40 = 6A+30
A= 5
A 's present age = A+ 10= 15
B's present age = B+10= 20
sum of their ages = 35
Similar questions