Math, asked by ss222176855, 11 months ago


Ten years ago, A's age was half of B's age. If
on the ratio of their present ages is 3 : 4, what
will be the sum of their present ages ?​

Answers

Answered by repallegnanasri
12

Answer:

35

Step-by-step explanation:

ten year's ago A's age : 1/2 of the B's age

at present A/B : 3/4

then A+10 / B+ 10 = 3/4

A+10 / 2A + 10 = 3/4

4A+40 = 6A+30

A= 5

A 's present age = A+ 10= 15

B's present age = B+10= 20

sum of their ages = 35

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