Question

Ten years ago, father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be. Find their present ages.

Answer 1

Answer:

Son's age= 12 years

Son's age= 12 yearsFather's age = 34 years.

Step-by-step explanation:

Let the present age of father be x and son be y

Therefore,

x - 10 = 12 ( y - 10 )

x - 10 = 12y - 120

x - 12y = - 110 --------------(1)

And,

x + 10 = 2 ( y + 10 )

x + 10 = 2y + 20

x - 2y = 10 ---------------(2)

Using (2) in (1)

x - 12y = -110

10 + 2y - 12y = -110

-10y = -120

y = 12 years

And,

x = 10 + 2y

= 10 + 2(12)

= 10 + 24

x = 34 years.

Hence, Son's age= 12 years

Hence, Son's age= 12 years Father's age = 34 years.

HOPE IT WILL HELP YOU ☺️.