Question

Ten years ago father was twelve times old as his sons and after ten years father will be twice as old as his sons find the present age of them ( with step by step explanation)​

Answer 1

$let \: the \: present \: age \: of \: son \: is \: x \\ and \: father \: age \: is \: \: y \\ according \: \: to \: question \\ 10 \: \: years \: ago \\ the \: age \: of \: his \: father \: y - 10 \\ the \: age \: of \: his \: son = x - 10 \\ according \: to \: question \\ y - 10 = 12(x - 10) \\ y - 12x = - 110.....(1) \\ 10 \: years \: after \\ y + 10 = 2(x + 10) \\ y - 2x = 10.....(2) \\ from \: (1) \: and \: (2) \: we \: get \\ - 10x = - 120 \\ x = 12 \\ put \: the \: valu \: of \: x \: in \: (2) \: then \: we \: get \\ y = 34$