Question

14. P and Q are any two points lying in the same segment of a
circle, as shown in the adjoining figure. Prove that
angle PAB+angle PBA = angle QAB+ angle QBA



PLEASE GIVE THE ANS WITH THE DIAGRAM
.....​

Answer 1

Answer:

let take a point R at PA and QB intersection.

Now, We know in a triangle sum of external angle is equal to sum of internal angle.

So,In triangle PRB,angle PRB=PAB+PBA

and

In triangle QRA,angle QRA=QBA+QAB and angle PRB and ORA are vertically opposite angle so,

PAB+PBA=QAB+QBA,Hence proved.