Question

Ten years ago the age of father was four times that of his son 5 years ago the age of father was three times that of his son find the present ages of father and son

Answer 1

Answer:

50 and 20

Step-by-step explanation:

Let present ages of father and son are F and S respectively

10 years ago F-10 = 4 (S-10)⇒ F-10 = 4S - 40⇒ 4S-F = 30

5 years ago F-5 = 3(S-5) ⇒ F-5 = 3S-15 ⇒ 3S - F = 10

by subtraction

S = 20

by substituting this value in first equation

4*20 - F = 30

F= 50