Question

The angle of depression of acar parked on the road from the top of 150 m high tower is 30 degree the distance of car from the tower is

Answer 1

Answer:

150√3

Step-by-step explanation:

• tan30=opp/adj
• 1/√3=150/adj
• adj=150√3
• here adjacent means distance between car and tower

Answer 2

Answer:

• The distance of car from the tower is 150√3 m

Step-by-step explanation:

Given,

• The angle of depression of acar parked on the road from the top of 150 m high tower is 30°

To Find:

• The distance of car from the tower is

Solution:

Let AB = 150 m be the height of the tower

DAC = 30°,

ACB = 30° (alternate angles)

In right traingle ABC,

$: \implies \sf \dfrac{AB}{BC} = tan30° \\ \\ : \implies \sf \frac{150}{BC} = \frac{1}{ \sqrt{3} } \\ \\ : \implies \sf \: \: BC = 150 \sqrt{3}$

Hence,

• The distance of car from the tower is 150√3 m.

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