Question

ten years ago the father was 12 times the age of son and ten years hence he will be twiceas old as his son will be.find present age

Answer 1

Hi there!
Here's the answer:

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Let the present age of Son be x years
& The present age of Father be y years

10 years ago,
Age of Son = x - 10
Age of Father = y - 10

Given,
At this time,
Father's Age = 12×( His son's Age)
=> y - 10 = 12(x - 10)
=> y - 10 = 12x - 120
=> 12x - y = 110 -----------------(1)

10 years hence,
Age of Son = x + 10
Age of Father = y + 10

Given,
At this time,
Father's Age = 2 × ( His son's Age)
=> y + 10 = 2(x + 10)
=> y + 10 = 2x + 20
=> 2x - y = -10 -----------------(2)



Do (1) - (2)
12x - y = 110
2x - y = -10
--------------------
10x = 120
=> x = 12

Substitute in (1)
12x - y = 110
=> 12(12) - y = 110
=> 144 - y = 110
=> y = 144 - 110
=> y = 34


•°• Present Age of Son = 12 years
& Present Age of Father = 34 years


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