Ten years later ,A will be twice as old as B and five years ago , A was three times as old B .What are the present ages of A and B
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Let the age of A be x
Let the age of B be y
A B
x y
x+10 = y+10
x+10 = 2 (y+10)
x+10 = 2y+20
x-2y =20-10
x-2y =10 --------(1)
A B
x = y
x-5 = y-5
x-5 = 3 (y-5)
x-5 = 3y -15
x- 3y = -15 +5
x - 3y = -10 --------(2)
Now you have eqn 1 and 2 through that you may know there present agaes
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