Question

Tens digit of a two-digit no. is three times its one's digit. if the sum of the number and the number got by reversing the digits 88, find the original no.

Answer 1

this is your respective answer.......

Answer 2

Step-by-step explanation:

let ones digit is x and tens digit is y then

according to question, y=3x

10y+x+y+10x=88

11y+11x=88

x+y=8

x+3x=8

4x=8

x=2

y=3x=3*2=6

so original number is 10y+x=10*6+2=62