Question

tension in string is................

Answer 1

In this question,

It is given that,

Mass of body = 10 kg
Acceleration due to Gravity = 10 m/s^2

$\cos(30) = \frac{ \sqrt{3} }{2}$

=> Normal Force = Mgsin¢

=> Normal Force =( 10 x 10 x 1/2) N

=> Normal Force = 50 N
Again,

Frictional Force=uMgcos¢

=> Frictional Force = 0.6 x 10 x 10 x Root3/2

=> Frictional Force = 51.96 N

Since, Here Frictional Force is greater that Normal Force.
So body will tend to come down by Normal Force but Frictional Force is greater. It means if we remove String attached to the body, Body won't come down.

Hence, Tension = 0 N

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Answer 2

Here is your answer

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