tension in the rope at the rigid support is (g=10m/s2)
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Answered by
487
case 1:
when the man ascends up the rope with acceleration of 2 m/s2.
we have T1 -mg =ma
or T1 = mg +ma
or T = 600 + (60x2 ) = 720 N
in case 2:
when the mans descend by a constant velocity
we have T 2= mg
so T2 = 50 x 10 =500 N
case 3:
when the man descends by 1 m/s2
we have
mg -T = ma
or
T = mg -ma
so T 3= 400-(40x1) = 360 N
so the net tension a the rigid support is = 720+500 +360 = 1580 N
when the man ascends up the rope with acceleration of 2 m/s2.
we have T1 -mg =ma
or T1 = mg +ma
or T = 600 + (60x2 ) = 720 N
in case 2:
when the mans descend by a constant velocity
we have T 2= mg
so T2 = 50 x 10 =500 N
case 3:
when the man descends by 1 m/s2
we have
mg -T = ma
or
T = mg -ma
so T 3= 400-(40x1) = 360 N
so the net tension a the rigid support is = 720+500 +360 = 1580 N
Answered by
50
Answer:
Answer is 1580 Newton
Explanation:
Just see the uploaded photo
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