Math, asked by doshivandana822, 23 hours ago

tere are 5 white, 7 red, 4 black and 2 blue identical balls in a box . one ball is selected at random from the box . find the probability that the selected balls is (1) either white pr blue, (2) either red or black, (3) not white, (4) nither white or black.​

Answers

Answered by Anonymous
78

Answer:

tere are 5 white, 7 red, 4 black and 2 blue identical balls in a box . one ball is selected at random from the box . find the probability that the selected balls is (1) either white pr blue, (2) either red or black, (3) not white, (4) nither white or black.

Answered by crankybirds30
17

What is the probability of 2 are red and one is blue

Work it out first where the order they are drawn is important.

RRB=718×617×316RRB=718×617×316

Then work out possible different orders they could be drawn RRB, RBR, BRR, there are three permutations P(3,1). so the answer is 7272×3=21272=0.07727272×3=21272=0.0772 = 7.72%

At least 2 are white

This is the probability that 3 are white plus the probability that 2 are white.

The probability that 3 are white is:

818×717×616=7102818×717×616=7102

The probability that exactly 2 are white is:

818×717×1016×C(3,2)=35306×3=35102818×717×1016×C(3,2)=35306×3=35102

Answer: 1. + 2. = 7102+35102=42102=717

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