Question

Teri finds a pile of money with at least $\$600$. if she puts $\$200$ of the pile in her left pocket, gives away $\frac45$ of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away $\$600$ of the original pile and kept the rest. what are the possible values of the number of dollars in the original pile of money

Answer 1

Let X be the amount in the pile.

What is left after putting $ 200 in the pile = X - $ 200

4/5 = 0.8

What she gives away = 0.8 (X - 200)

The remaining is : 0.2 (X - 200) what she puts in her right pocket.

200 + 0.2(X - 200) > X - 600

200 - 0.2X - 40 > X - 600

Solving the inequality we have :

160 + 0.2x > X - 600

760 > X - 0.2X

760 > 0.8X

950 > X

This implies :

X < 950

It is said :

X ≥ 600

The possible range of X is thus :

600 ≤ X < 950

Answer 2

Answer:

Step-by-step explanation:

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