Physics, asked by satyamku1221, 1 year ago

Terminal velocity of a 2cm radius ball in a viscous liquid is 20cm s^-1.what would be the terminal velocity if the radius of the ball were halved

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Answered by mukadumabbas
0

https://books.google.ae/books?id=dvwR7XtAwr0C&pg=PA690&lpg=PA690&dq=Terminal+velocity+of+a+2+cm+radius+ball+in+a+viscous+liquid+is+20cm+s%5E-1.what+would+be+the+terminal+velocity+if+the+radius+of+the+ball+were+halved&source=bl&ots=-bzZltQAPz&sig=0tYivrnxOE6LvUu1k7t7R3lZ0Yk&hl=en&sa=X&ved=2ahUKEwj2xIO6kavdAhVVb30KHagQDDwQ6AEwAnoECAcQAQ#v=onepage&q=Terminal%20velocity%20of%20a%202%20cm%20radius%20ball%20in%20a%20viscous%20liquid%20is%2020cm%20s%5E-1.what%20would%20be%20the%20terminal%20velocity%20if%20the%20radius%20of%20the%20ball%20were%20halved&f=false

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Answered by Anonymous
30

Answer:

Photosystem II (or water-plastoquinone oxidoreductase) is the first protein complex in the light-dependent reactions of oxygenic photosynthesis. It is located in the thylakoid membrane of plants, algae, and cyanobacteria. Being a light reaction, non-cyclic photophosphorylation occurs in the thylakoid membrane. First, a water molecule is broken down into 2H+ + 1/2 O2 + 2e− by a process called photolysis (or light-splitting). The deficit of electrons is replenished by taking electrons from another molecule of water.

Explanation:

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