Question

Test II. Evaluate the following functions at x = -2.

$8. \: f(x) \: = {x}^{3} - 64$

$9. \: g(x) = \sqrt{5 - x = }$
$10. \: g(x) = \frac{x + 3}{ {x} ^ {2} + 7x + 12 }$
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Answer 1

x = -2

1)

f(-2) = x³ - 64

= -2³ - 64

= -8 - 64

= -72

2)

g(-2) = √(5 - x)

= √(5 - (-2))

= √7

3)

g(-2) = (x + 3)/(x² + 7x + 12)

= (-2 + 3)/(-2² + 7(-2) + 12)

= 1/(4 - 14 + 12)

= 1/(4 - 2) = 1/2

Answer 2

Answer:

Step-by-step explanation:

$1) \text{The value of f(x) at x=-2 is}\\~~~~~~f(-2) = (-2)^3 - 64\\~~or,~ f(-2) = -8 - 64\\~~or,~f(-2) = -72\\2) \text{The value of g(x) at x = -2 is}\\~~~~g(-2) = \sqrt{5-(-2)}\\~~or,~g(-2) = \sqrt{7}\\3) \text{The value of g(x) at x = -2 is}\\\\~~~~g(-2) = \frac{-2+3}{(-2)^2 + 7(-2) + 12}\\~~or,~g(-2) = \frac{1}{4-14+12}\\\\~~or,~g(-2) = \frac{1}{2}$