Question

test the continuity of the following function at the point indicated against them ​

Answer 1

$\frac{ {x}^{3} - 3 {}^{3} }{ {x}^{2} - {3}^{2} } \\ = > \frac{(x - 3)( {x}^{2} + 3x + {3}^{2} ) }{(x - 3)(x + 3)} \\ = > \frac{ {x}^{2} + 3x + 9 }{x + 3} \: \: \: \: \: at \: x = 3 \\ = > \frac{9 + 9 + 9}{6} = \frac{9}{2} \\ therefore \: the \: given \: function \\ \: is \: continuous \: at \: x = 3$

Answer 2

Answer:

here is your answer

Step-by-step explanation:

x³-3³/ x²-3²

= (x- 3) (x²+ 3x+ 3²)/ (x- 3) (x+ 3)

at x= 3

=x²+ 3x+ 9/ x+ 3

=9+ 9+ 9/ 6

=9/ 2

so the given function will go on at x= 3