Test the dimensionally if the equation v2=u2+2as may be correct. Where V is the final velocity, u is the initial velocity, a is the acceleration & s is the displacement
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Velocity is displacement/time
Displacement is nothing but length so the dimensional formula is L and time is T so L/T =====> LT^-1.
Both initial and final velocities have the same dimensional formula.
Acceleration is velocity/time
Velocity is LT^-1 which we had derived already so left out is time which is T so now LT^-1/T ===> LT^-2
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