Question

Test the dimwnsionally if the equation v2=u2+2as may be correct. Where V is the final velocity, u is the initial velocity, a is the acceleration & s is the displacement

Answer 1

We can check the correctness of equation by Dimensional Analysis.

Equation: V²-U²=2as

where V=u=velocities = Dimension=LT⁻¹

a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²

S=Distance=L

R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]

L.H.S=v²-u²=[LT⁻¹]²=[L²T⁻²]

Therefore  L.H.S=R.H.S

Hence we can say equation is correct