Physics, asked by toshuuu6364, 1 year ago

Test the dimwnsionally if the equation v2=u2+2as may be correct. Where V is the final velocity, u is the initial velocity, a is the acceleration & s is the displacement

Answers

Answered by Anonymous
2

We can check the correctness of equation by Dimensional Analysis.

Equation: V²-U²=2as


where V=u=velocities = Dimension=LT⁻¹


a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²


S=Distance=L


R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]


L.H.S=v²-u²=[LT⁻¹]²=[L²T⁻²]


Therefore  L.H.S=R.H.S


Hence we can say equation is correct


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