Test the divisibility of 176 by 2,3,5,9,11
Answers
Divisibility by2: last digit is even so divisible by2
Divisibility by 3: sum of the digits 1+7+6=14.
14 is not divisible by 3
hence, not divisible by 3.
Divisibility by 5: last digit is not 0 or 5.
hence not divisible by 5.
Divisibility by 9: sum of the digit is 14.
14 is not divisible by 9.
hence, not divisible by 9.
Divisibility by 11: sum of digits at odd places=1+6=7
sum of digits at even places=7
7-7=0
hence, divisible by 11.
The following number is divisible by 2 and 7 and not divisible by 3, 5 and 9.
Answer:
The following number is divisible by 2 and 7 and not divisible by 3, 5 and 9.
Explanation:
Divisibility by 2: last digit is even so divisible by 2
Divisibility by 3: sum of the digits 1+7+6=14.
14 is not divisible by 3
hence, not divisible by 3.
Divisibility by 5: last digit is not 0 or 5.
hence not divisible by 5.
Divisibility by 9: sum of the digit is 14.
14 is not divisible by 9.
hence, not divisible by 9.
Divisibility by 11: sum of digits at odd places=1+6=7
sum of digits at even places=7
7-7=0
hence, divisible by 11.
Therefore, the following number is divisible by 2 and 7 and not divisible by 3, 5 and 9.
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