test the divisibily of 94563 by 7
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Hey dear,
The divisibility rule of 7 is that
=Take the last digit of number ,double it and subtract from the remaining number. Do this thing again and again one digit remain which is 7 or 0.
If it is 0 or 7 so the original number would be divided by 7.
Let's do it
9456-6=9450
945-0=945
94-10=84
8-8=0
As in the end of process 0 is come .
So, the original number=>94563 will be divided by 7.
perfectly definitely pure correct answer.
hope it helps you and Mark me as brainliest and follow me
The divisibility rule of 7 is that
=Take the last digit of number ,double it and subtract from the remaining number. Do this thing again and again one digit remain which is 7 or 0.
If it is 0 or 7 so the original number would be divided by 7.
Let's do it
9456-6=9450
945-0=945
94-10=84
8-8=0
As in the end of process 0 is come .
So, the original number=>94563 will be divided by 7.
perfectly definitely pure correct answer.
hope it helps you and Mark me as brainliest and follow me
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