Math, asked by Kamal123455909, 11 months ago

test the divisible by 3 then find the least value of x​

Answers

Answered by VineetaGara
2

Answer:

The least value of X is 1 with which it makes 516 and it is divisible by 3.

Step-by-step explanation:

Your quesation is wrong. The quesation should be like "Test if 5X6 is divisible by 3 then find the value of X?"

Now the answer;

Any number is divisible by 3 if the sum of the digits is divisible by 3.

So; we can put the value (from 0 to 9) of X and check if the sum of the digits is divisible by 3.

When X=0

5+0+6=11 (not divisible by 3)

When X=1

5+1+6=12 (divisible by 3)

When X=2

5+2+6=13 (not divisible by 3)

When X=3

5+3+6=14 (not divisible by 3)

When X=4

5+4+6=15 (divisible by 3)

When X=5

5+5+6=16 (not divisible by 3)

When X=6

5+6+6=17 (not divisible by 3)

When X=7

5+7+6=18 (divisible by 3)

When X=8

5+8+6=19 (not divisible by 3)

When X=9

5+9+6=20 (not divisible by 3)

The least value of X is 1 with which it makes 516 and it is divisible by 3.

Answered by sahiduzzamansaied
1

Step-by-step explanation:

Any number is divisible by 3 if the sum of the digits is divisible by 3. So; we can put the value (from 0 to 9) of X and check if the sum of the digits is divisible by 3. The least value of X is 1 with which it makes 516 and it is divisible by 3.

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