Question

test the function of relative maximum and minimum for xy+(9/x)+(3/y)​

Answer 1

Answer:

the correct answer for this question is

9

Step-by-step explanation:

.

Answer 2

The relative minimum is at (x,y) = (3,1)

• The moment at which the function shifts from increasing to decreasing is known as a relative maximum (making that point a "peak" in the graph).
• A similar point where the function shifts from dropping to growing is known as a relative minimum point (making that point a "bottom" in the graph). Finding the places where a function changes direction requires one more step, assuming you are already familiar with finding rising and decreasing intervals of a function.
• We must determine where the sign of our first derivative changes in order to locate relative maximums. To achieve this, locate the point at which your first derivative equals zero. We only need to test points on the range from -5 to 0, as we are only interested in that range.

Here, the function is,

$xy+\frac{9}{x} +\frac{3}{y}$.

Then, the relative minimum is at (x,y) = (3,1)

Now, putting the values we get,

$3.1+\frac{9}{3} +\frac{3}{1} \\=9$

Hence, the relative minimum is at (x,y) = (3,1).

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