Chemistry, asked by Varunrf1216, 1 year ago

Test to detect the nitrogen present in organic compound

Answers

Answered by deb15
1
The carbon and nitrogen present in the organic compound on fusion with sodium metal gives sodium cyanide (NaCN) soluble in water. This is converted in to sodium ferrocyanide by the addition of sufficient quantity of ferrous sulphate. Ferric ions generated during the process react with ferrocyanide to form prussian blue precipitate of ferric ferrocyanide.
Na + C + N → NaCN

6NaCN + FeSO 4 → Na 4 [Fe(CN) 6 ] + Na 2 SO 4

Na4 [Fe(CN) 6 ] + Fe3+ → Fe4 [Fe(CN) 6 ] 3
Answered by Anonymous
1

Hey brainly user

Here is your answer

\huge{\textbf{\underline{Detection\:of\:nitrogen}}}

☞The sodium fusion extract is boiled with FeSO4 and then acidified with concentrated sulfuric acid

☞The formation of Prussian blue colour confirms the presence of nitrogen

☞The Prussian blue colour obtained in lassaigne's test is due to the formation of ferric ferro cyanide

\bold{6NaCN+FeSO_4{\rightarrow}Na_4[Fe(CN)_6]+Na_2SO_4}}}

\bold{3Na_4[Fe(CN)_6]+4FeCl_3{\rightarrow}Fe_4[Fe(CN)_6]_3+12NaCl}}

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