Question

$1 \div 7 {(3x - 5)}^{2} = 28. \\ \\ find \: \: \: x$
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Answer 1

Answer:

This is my answer

Step-by-step explanation:

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Answer 2

Answer:

(3x-5)^2=28*7

9x^2-30x+25-196=0

3(3x^2-10x-57)=0

3x^2-19x+9x-57=0

x(3x-19)+3(3x-19)=0

(x+3)(3x-19)=0

x= -3,19/3