Question

$1 \frac{4x - 1 \frac{2y + 1$
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Answer 1

$\huge{\overbrace{\underbrace{\mathbb{\green{ANSWER}}}}}$

$\frac{1}{4x - 1} \frac{1}{2y + 1} \\ = > \frac{1}{(4x - 1)(2y + 1)} \\ = > \frac{1}{8xy - 2y + 4x - 1} \\ = > \frac{1}{4x - 2y + 8xy - 1}$

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