algebraic identities
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Answer:
10b²-3c²
Step-by-step explanation:
⇒ 100b²-60bc+9c²
Using identity, a²-2ab+b²= (a-b)²
Where,
- a = 100b²
- b = 9c²
⇒ (100b)²-(60bc)+(9c)²
⇒ 10b²-2(10b)(3c)+3c²
⇒ 10b²-3c²
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