Question

$100x^{2} +1900x-23600$
solve this plz

Answer 1

$100 {x}^{2} + 1900x - 23600 = 0 \\ = > 100 {x}^{2} + 1900x = 23600$
$given \\ \\ a = 100 \\ b = 1900 \\ c = 23600$

$x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{ - 1900 ± \sqrt{ {3610000-9440000} }{200}$

$x = \frac{ - 1900 ± \sqrt{ {-5830000} }{200}$

$x = \frac{ - 1900 ± 2414.5 }{200}$

Answer 2

Here is your answer friend.