Math, asked by adithyasanda2006, 1 year ago




 ({16}^{ - 115})whole power  \frac{5}{2}

Answers

Answered by Swarup1998
0

Answer:

2^(- 1150)

Step-by-step explanation:

Now, {16^(-115)}^(5/2)

= {(4^2)^(-115)}^(5/2)

= {4^(2 × - 115)}^(5/2)

= 4^{- (2 × 115 × 5 ÷ 2)}

= 4^(- 115 × 5)

= 4^(- 575)

= 2^(- 2× 575)

= 2^(- 1150)

Remark:

While solving this problem, the only intensity should be to simplify the value as the power to the smallest value in natural numbers.

The value of 2^(- 1150) is very small and can be taken as 0.

Laws of indices:

1. a^b × c^b = (a × c)^b

2. a^b × a^c = a^(b × c)

3. a^(- b) = 1/(a^b)

4. a^0 = 1

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