Question

$16x {}^{2} + 112x + 132$
Factorise the following expression.

Answer 1

Answer:

Done = Middle term factorisation.

Step-by-step explanation:using Sridharacharya method,

a=16, b=112, c=132

= [-b ±√(b²- 4ac)]÷2a  == Formula

= [-112 ±√(112²- 4 x 16 x 132)]÷2 x 16

= [-112 ± √(12544 - 8448)]÷32

= [-112 ± √(4096)]÷32

= [-112 ± 64]÷32

= [-112 + 64]÷32           or         [-112 - 64]÷32

x = -3/2                         or         x = -11/2