Question

${2}^{2} \times {2}^{ - 7} find \:$
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Answer 1

Answer:

${2}^{2} \times {2}^{ - 7} find \:$

According to Question,

${a}^{m} \times {a}^{ n} ={a}^{m+n} \:$

so,

${2}^{2-7}$

${2}^{-5}$

Answer 2

$\huge\red{✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏}$

$\huge\underline\blue{Question}$

$Find:$

$\orange{Q.\:{2}^{2} \times {2}^{ - 7} }$

$\huge\underline\purple{Answer}$

$In \:multiplication ,$

${We \:add\: the \:index \:or\:power\: like;}$

$=>a {}^{m} \times a {}^{n } = a {}^{(m + n)}$

$A/Q,$

$\green{= > 2 {}^{2} \times 2 {}^{ - 7} }$

$\green{= > 2 {}^{2 + ( - 7)} }$

$\green{= > 2 {}^{2 - 7}}$

$\green{ = > 2 {}^{ - 5}}$

$\orange{Thank\:You..!!!}$

$\huge\red{✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏}$