Question

$2 \div x + 1 + 3 \div 2(x - 2) = 23 \div 5x$
​

Answer 1

Step-by-step explanation:

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

gxjgdgnchjcbmcvxnvnvnvvmbcbkbxgjxgjxvnvnvngcgkxkgxgkxgj,fjxgnxfnxjgxgjcnbbmcbk kbxjvxjgx

Answer 2

Step-by-step explanation:

$\frac{2}{x} + 1 + \frac{3}{2(x - 2)} = \frac{23}{5x} \\ = > \frac{2 + x}{x} + \frac{3}{2x - 4} = \frac{23}{5x} \\ = > \frac{(2x - 4)(2 + x) +3x }{x(2x - 4)} = \frac{23}{5x} \\ = > \frac{4x +2 {x}^{2} - 8 - 4x + 3x}{2 {x}^{2} - 4x} = \frac{23}{5x} \\ = > \frac{2 {x}^{2} + 3x - 8 }{2 {x}^{2} - 4x } = \frac{23}{5x} \\ = > {10 {x}^{3} + 15 {x}^{2} - 40x } = 46 {x}^{2} - 92x \\ = > 10 {x}^{3} - 31 {x}^{2} + 52x = 0$

Hope it helps you......