Question

${2}^{x + 1 } {2}^{x - 1} = 320$
find the value of x​

Answer 1

Answer:

$\frac{321}{y}$

Step-by-step explanation:

${2}^{x + 1} {2}^{x - 1} = 320 \\ \\ let \: us \: take \: the \: expontents \\ \: alone \\ \\( x + 1)(x - 1) = 320 \\ \\ ( {x }^{2} - {1)}^{2} = 320 \\ \\ {x}^{2} = 320 + 1 \\ \\ {x}^{2} = 321 \\ \\ x \times x = 321 \\ \\ let \: us \: consider \: x \: as \: constant \\ \\ x = \frac{321}{x}$

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