Math, asked by aleem1471964, 10 months ago


2 {x }^{2}  - 2 \sqrt{6}  + 3factorises \:

Answers

Answered by umiko28
7

Answer:

\huge\underline{ \underline{ \red{your \: \: answer}}}

Step-by-step explanation:

 \sf\blue{ {2x}^{2}  - 2 \sqrt{6}x + 3 } \\  \sf\blue{ =  >  {2x}^{2}  -  \sqrt{6} -  \sqrt{6}  + 3 } \\  \sf\blue{ =  >  \sqrt{2}x( \sqrt{2}x - \sqrt{3} ) -  \sqrt{3}( \sqrt{2}x -  \sqrt{3}  )   } \\  \sf\blue{ =  > ( \sqrt{2}x -  \sqrt{3}  )( \sqrt{2}x  -  \sqrt{3} )} \\  \sf\pink{x =  \frac{ \sqrt{3} }{ \sqrt{2} } } \\  \sf\purple{x =  \frac{ \sqrt{3} }{ \sqrt{2} } } \\ \large\boxed{ \fcolorbox{green}{yellow}{hope \: it \: help \: you}}

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