![2 x ^ { 2 } y - [ 4 y ^ { 2 } x - ( 3 x ^ { 2 } y - ( 4 x ^ { 2 } y - 2 x y ^ { 2 } ) ] 1](https://tex.z-dn.net/?f=2+x+%5E+%7B+2+%7D+y+-+%5B+4+y+%5E+%7B+2+%7D+x+-+%28+3+x+%5E+%7B+2+%7D+y+-+%28+4+x+%5E+%7B+2+%7D+y+-+2+x+y+%5E+%7B+2+%7D+%29+%5D+1 "2 x ^ { 2 } y - [ 4 y ^ { 2 } x - ( 3 x ^ { 2 } y - ( 4 x ^ { 2 } y - 2 x y ^ { 2 } ) ] 1")
please do it in copy
Answers
Answered by
1
Find the value of X and Y if
2X+3Y=[
2
4
3
0
] 3X+2Y=[
2
−1
−2
5
]
→ let Assume [
2
4
3
0
] = A
[
2
−1
−2
5
] = B
→2x+3y=A __ (i)
3x+2y=B __ (ii)
→ multiple equation (i) with 2 & equation (ii) with (3)
4x+6y=2A
9x+6y=3B
________________
−5x=2A−3B
∴x=
5
−1
[2A−3B]
∴x=
5
3B
−
5
2A
=
5
3
[
2
−1
−2
5
]−
5
2
[
2
4
3
0
]
=[
6/5
−3/5
−6/5
3
]−[
4/5
8/5
6/5
0
]
=[
6/5
−3/5
−4/5
−8/5
−4/5
3
−6/5
−0
]
∴x=[
1/5
−11/5
−12/5
3
]
→ value of x put in equation (i)
∴[
2/5
−22/5
−24/5
6
]+3y=[
2
4
3
0
]
∴3y=[
2−2/5
4+22/5
3+24/5
0−6
]=[
8/5
42/5
39/5
−6
]
∴y=[
8/15
42/15
39/15
−2
]
Answered by
0
Answer:
2(22)(3)−(4(32)(2)−(3(23)−(4(23)−2(22)(3))))
2(22)(3)−(4(32)(2)−(3(23)−(4(23)−2(22)(3))))
=−32
Similar questions