Two angles of a triangle are equal and third angle is greater than each one of them by 18°.find the angle.
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Let the two equal Angles of the triangle be X
now A/Q
X+X +X+ 18 =180
then 3x+18=180
3x=180-18
3x=162
x=162/3
X=54
hence
angles of the triangle are 54,54 and72
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