Math, asked by sfffffffffffffffffff, 11 months ago

2^{x} * 3^{x} dx

calculate the indefinite integral

Answers

Answered by Anonymous
0

Answer:

\bold\red{\frac{ {6}^{x} }{ ln(6) }  + c}

Step-by-step explanation:

We have to integrate,

\int {2}^{x}  \times  {3}^{x} dx

We know that,

 {a}^{m} \times  {b}^{m}   =  {(ab)}^{m}

Therefore,

we get,

\int {(2 \times 3)}^{x} dx \\  \\  = \int {6}^{x} dx

Now, we know that,

\int {a}^{m}  =   \frac{ {a}^{m} }{ ln(a) }

Therefore,

we get,

Integration

 =   \bold{\frac{ {6}^{x} }{ ln(6) }  + c}

where,

c is an arbitrary constant

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