Question

what is the molality of C2 h5 0h in water solution which will freezing at -10 degree centigrade molecular weight of C2 h5 0h is equal to 46 KF for water is equal to 1.86​

Answer 1

Answer:

the correct answer is 5.3m

Explanation:

we know

depression in freezing point = depression constant × molality e.i., ∆T=Kf× m

Here ∆T = 10°C [ we neglected sign]

Kf=1.86

Now, 10 = 1.86 m

m = 10)/1.86= 5.37

Hence molality = 5.3m

Answer 2

Answer:

hii dost eska answer hoga 5.3 mole