Math, asked by sfffffffffffffffffff, 9 months ago

2^{x}+3^{x}dx


calculate the indefinite integral
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Answered by Anonymous
6

Answer:

\bold\red{ \frac{ {2}^{x}   }{  ln(2)  }  +  \frac{ {3}^{x} }{ ln(3) }+c}

Step-by-step explanation:

We have to find the integration of,

 \int( {2}^{x}  +  {3}^{x} )dx

We know that,

Integration of,

\int {a}^{x}  =  \frac{ {a}^{x} }{ ln(a) }

So, according to this,

we get,

Integration

\bold{ \frac{ {2}^{x}   }{  ln(2)  }  +  \frac{ {3}^{x} }{ ln(3) }+c}

where, c is an arbitrary constant

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