Question

$2a {}^{2} + 7a + 6 \\ factorise \: the \: above \: mention \: question$
​

Answer 1

Step-by-step explanation:

2a^2-4a-3a+6

taking common

2a(a-2)-3(a+2)

(2a-3)(a-2)

Answer 2

$\huge\underline\purple{\sf Answer:-}$

➡2a^2+ 7a + 6

➡2a^2+ 4a + 3a + 6

➡2a(a+2)+3(a+2)

➡(a+2)(2a+3)

$\huge\mathfrak\blue{Thanks :)}$